Base | Representation |
---|---|
bin | 100101100101111100000… |
… | …0001000000001000100011 |
3 | 200021221012000121001202120 |
4 | 1023023320001000020203 |
5 | 1134122411143431201 |
6 | 14553315442515323 |
7 | 1042165634563614 |
oct | 113137001001043 |
9 | 20257160531676 |
10 | 5166711702051 |
11 | 1712210072819 |
12 | 6b5415365b43 |
13 | 2b62ac9a5503 |
14 | 13c0da80bc0b |
15 | 8e5e852b536 |
hex | 4b2f8040223 |
5166711702051 has 16 divisors (see below), whose sum is σ = 7122888450048. Its totient is φ = 3327870816000.
The previous prime is 5166711702029. The next prime is 5166711702059. The reversal of 5166711702051 is 1502071176615.
It is not a de Polignac number, because 5166711702051 - 27 = 5166711701923 is a prime.
It is a super-2 number, since 2×51667117020512 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5166711701994 and 5166711702012.
It is not an unprimeable number, because it can be changed into a prime (5166711702059) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 45706350 + ... + 45819251.
It is an arithmetic number, because the mean of its divisors is an integer number (445180528128).
Almost surely, 25166711702051 is an apocalyptic number.
5166711702051 is a deficient number, since it is larger than the sum of its proper divisors (1956176747997).
5166711702051 is a wasteful number, since it uses less digits than its factorization.
5166711702051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 91526242.
The product of its (nonzero) digits is 88200, while the sum is 42.
Adding to 5166711702051 its reverse (1502071176615), we get a palindrome (6668782878666).
The spelling of 5166711702051 in words is "five trillion, one hundred sixty-six billion, seven hundred eleven million, seven hundred two thousand, fifty-one".
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