Base | Representation |
---|---|
bin | 100101101010110101110… |
… | …1000011001000000110011 |
3 | 200022221100211222012022110 |
4 | 1023111223220121000303 |
5 | 1134310442240421003 |
6 | 15002220345340403 |
7 | 1043020603211433 |
oct | 113255350310063 |
9 | 20287324865273 |
10 | 5177241342003 |
11 | 17167238490a5 |
12 | 6b7473797703 |
13 | 2b729a324bb3 |
14 | 13c8190402c3 |
15 | 8ea12b59a03 |
hex | 4b56ba19033 |
5177241342003 has 4 divisors (see below), whose sum is σ = 6902988456008. Its totient is φ = 3451494228000.
The previous prime is 5177241341981. The next prime is 5177241342041. The reversal of 5177241342003 is 3002431427715.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 5177241342003 - 26 = 5177241341939 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5177241342503) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 862873556998 + ... + 862873557003.
It is an arithmetic number, because the mean of its divisors is an integer number (1725747114002).
Almost surely, 25177241342003 is an apocalyptic number.
5177241342003 is a deficient number, since it is larger than the sum of its proper divisors (1725747114005).
5177241342003 is a wasteful number, since it uses less digits than its factorization.
5177241342003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1725747114004.
The product of its (nonzero) digits is 141120, while the sum is 39.
Adding to 5177241342003 its reverse (3002431427715), we get a palindrome (8179672769718).
The spelling of 5177241342003 in words is "five trillion, one hundred seventy-seven billion, two hundred forty-one million, three hundred forty-two thousand, three".
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