Base | Representation |
---|---|
bin | 1001101010100101… |
… | …10101001000111001 |
3 | 111101122012101111111 |
4 | 10311102311020321 |
5 | 41111402032433 |
6 | 2214524200321 |
7 | 242406405514 |
oct | 46522651071 |
9 | 14348171444 |
10 | 5189095993 |
11 | 2223122694 |
12 | 10099990a1 |
13 | 649098a03 |
14 | 373245d7b |
15 | 205859dcd |
hex | 1354b5239 |
5189095993 has 4 divisors (see below), whose sum is σ = 5309772688. Its totient is φ = 5068419300.
The previous prime is 5189095991. The next prime is 5189096009. The reversal of 5189095993 is 3995909815.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5189095993 - 21 = 5189095991 is a prime.
It is a super-3 number, since 3×51890959933 (a number of 30 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5189095991) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60338283 + ... + 60338368.
It is an arithmetic number, because the mean of its divisors is an integer number (1327443172).
Almost surely, 25189095993 is an apocalyptic number.
It is an amenable number.
5189095993 is a deficient number, since it is larger than the sum of its proper divisors (120676695).
5189095993 is a wasteful number, since it uses less digits than its factorization.
5189095993 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 120676694.
The product of its (nonzero) digits is 3936600, while the sum is 58.
The square root of 5189095993 is about 72035.3801475358. The cubic root of 5189095993 is about 1731.2664046407.
The spelling of 5189095993 in words is "five billion, one hundred eighty-nine million, ninety-five thousand, nine hundred ninety-three".
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