Base | Representation |
---|---|
bin | 110000010111001100… |
… | …010010111000100001 |
3 | 11222001000000121200101 |
4 | 300113030102320201 |
5 | 1322322222102333 |
6 | 35504500222401 |
7 | 3515561503021 |
oct | 602714227041 |
9 | 158030017611 |
10 | 51928706593 |
11 | 20028445945 |
12 | a09299aa01 |
13 | 4b8751492a |
14 | 272894ba81 |
15 | 153dd7367d |
hex | c17312e21 |
51928706593 has 4 divisors (see below), whose sum is σ = 51929257860. Its totient is φ = 51928155328.
The previous prime is 51928706581. The next prime is 51928706633. The reversal of 51928706593 is 39560782915.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It can be written as a sum of positive squares in 2 ways, for example, as 31107082384 + 20821624209 = 176372^2 + 144297^2 .
It is a cyclic number.
It is not a de Polignac number, because 51928706593 - 217 = 51928575521 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51928706503) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 94780 + ... + 335917.
It is an arithmetic number, because the mean of its divisors is an integer number (12982314465).
Almost surely, 251928706593 is an apocalyptic number.
It is an amenable number.
51928706593 is a deficient number, since it is larger than the sum of its proper divisors (551267).
51928706593 is a wasteful number, since it uses less digits than its factorization.
51928706593 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 551266.
The product of its (nonzero) digits is 4082400, while the sum is 55.
The spelling of 51928706593 in words is "fifty-one billion, nine hundred twenty-eight million, seven hundred six thousand, five hundred ninety-three".
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