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5198302569601 = 12739408062059
BaseRepresentation
bin100101110100101001011…
…1110100110010010000001
3200101221201122101102011001
41023221102332212102001
51140132110424211401
615020022304452001
71044364532535361
oct113512276462201
920357648342131
105198302569601
111724651310119
126bb57101a001
132b927582664b
1413d8562509a1
1590346b4d601
hex4ba52fa6481

5198302569601 has 4 divisors (see below), whose sum is σ = 5198710644400. Its totient is φ = 5197894494804.

The previous prime is 5198302569589. The next prime is 5198302569637. The reversal of 5198302569601 is 1069652038915.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5198302569601 - 237 = 5060863616129 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5198302569671) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 204018291 + ... + 204043768.

It is an arithmetic number, because the mean of its divisors is an integer number (1299677661100).

Almost surely, 25198302569601 is an apocalyptic number.

It is an amenable number.

5198302569601 is a deficient number, since it is larger than the sum of its proper divisors (408074799).

5198302569601 is a wasteful number, since it uses less digits than its factorization.

5198302569601 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 408074798.

The product of its (nonzero) digits is 3499200, while the sum is 55.

The spelling of 5198302569601 in words is "five trillion, one hundred ninety-eight billion, three hundred two million, five hundred sixty-nine thousand, six hundred one".

Divisors: 1 12739 408062059 5198302569601