Base | Representation |
---|---|
bin | 110000011011011100… |
… | …010000100000101001 |
3 | 11222012222011200220110 |
4 | 300123130100200221 |
5 | 1322444000000131 |
6 | 35515524244533 |
7 | 3520415464443 |
oct | 603334204051 |
9 | 158188150813 |
10 | 52000000041 |
11 | 2006470a750 |
12 | a0b2840749 |
13 | 4b992170c2 |
14 | 27341c9493 |
15 | 1545257646 |
hex | c1b710829 |
52000000041 has 16 divisors (see below), whose sum is σ = 78924902400. Its totient is φ = 30144927120.
The previous prime is 52000000009. The next prime is 52000000043. The reversal of 52000000041 is 14000000025.
It is not a de Polignac number, because 52000000041 - 25 = 52000000009 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 51999999963 and 52000000026.
It is not an unprimeable number, because it can be changed into a prime (52000000043) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 34254841 + ... + 34256358.
It is an arithmetic number, because the mean of its divisors is an integer number (4932806400).
Almost surely, 252000000041 is an apocalyptic number.
It is an amenable number.
52000000041 is a deficient number, since it is larger than the sum of its proper divisors (26924902359).
52000000041 is a wasteful number, since it uses less digits than its factorization.
52000000041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 68511236.
The product of its (nonzero) digits is 40, while the sum is 12.
Adding to 52000000041 its reverse (14000000025), we get a palindrome (66000000066).
The spelling of 52000000041 in words is "fifty-two billion, forty-one", and thus it is an aban number and an uban number.
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