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52054513001 = 152123342187
BaseRepresentation
bin110000011110101100…
…001101010101101001
311222100202202020121222
4300132230031111221
51323101423404001
635525152511425
73521650026401
oct603654152551
9158322666558
1052054513001
1120092463087
12a108b4b575
134ba75c26aa
14273b539801
151549e2461b
hexc1eb0d569

52054513001 has 4 divisors (see below), whose sum is σ = 52055007312. Its totient is φ = 52054018692.

The previous prime is 52054512997. The next prime is 52054513051. The reversal of 52054513001 is 10031545025.

52054513001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 52054513001 - 22 = 52054512997 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (52054513051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18971 + ... + 323216.

It is an arithmetic number, because the mean of its divisors is an integer number (13013751828).

Almost surely, 252054513001 is an apocalyptic number.

It is an amenable number.

52054513001 is a deficient number, since it is larger than the sum of its proper divisors (494311).

52054513001 is a wasteful number, since it uses less digits than its factorization.

52054513001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 494310.

The product of its (nonzero) digits is 3000, while the sum is 26.

The spelling of 52054513001 in words is "fifty-two billion, fifty-four million, five hundred thirteen thousand, one".

Divisors: 1 152123 342187 52054513001