Base | Representation |
---|---|
bin | 110000100000001111… |
… | …001001111010100001 |
3 | 11222102120120001012020 |
4 | 300200033021322201 |
5 | 1323130043414413 |
6 | 35531520452053 |
7 | 3522413350146 |
oct | 604017117241 |
9 | 158376501166 |
10 | 52080451233 |
11 | 200a6069938 |
12 | a11577a029 |
13 | 4bacaa4965 |
14 | 2740b6c3cd |
15 | 154c349c23 |
hex | c203c9ea1 |
52080451233 has 4 divisors (see below), whose sum is σ = 69440601648. Its totient is φ = 34720300820.
The previous prime is 52080451207. The next prime is 52080451249. The reversal of 52080451233 is 33215408025.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 52080451233 - 28 = 52080450977 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 52080451194 and 52080451203.
It is not an unprimeable number, because it can be changed into a prime (52080451253) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8680075203 + ... + 8680075208.
It is an arithmetic number, because the mean of its divisors is an integer number (17360150412).
Almost surely, 252080451233 is an apocalyptic number.
It is an amenable number.
52080451233 is a deficient number, since it is larger than the sum of its proper divisors (17360150415).
52080451233 is a wasteful number, since it uses less digits than its factorization.
52080451233 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17360150414.
The product of its (nonzero) digits is 28800, while the sum is 33.
Adding to 52080451233 its reverse (33215408025), we get a palindrome (85295859258).
The spelling of 52080451233 in words is "fifty-two billion, eighty million, four hundred fifty-one thousand, two hundred thirty-three".
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