Base | Representation |
---|---|
bin | 110000100001011011… |
… | …110011011110010011 |
3 | 11222110222100212211201 |
4 | 300201123303132103 |
5 | 1323200214410103 |
6 | 35533515252031 |
7 | 3523046214625 |
oct | 604133633623 |
9 | 158428325751 |
10 | 52100544403 |
11 | 20106443166 |
12 | a12044a017 |
13 | 4bb3cbb5cb |
14 | 27436bcc15 |
15 | 154deb851d |
hex | c216f3793 |
52100544403 has 4 divisors (see below), whose sum is σ = 54365785488. Its totient is φ = 49835303320.
The previous prime is 52100544401. The next prime is 52100544407. The reversal of 52100544403 is 30444500125.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 52100544403 - 21 = 52100544401 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (52100544401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1132620508 + ... + 1132620553.
It is an arithmetic number, because the mean of its divisors is an integer number (13591446372).
Almost surely, 252100544403 is an apocalyptic number.
52100544403 is a deficient number, since it is larger than the sum of its proper divisors (2265241085).
52100544403 is a wasteful number, since it uses less digits than its factorization.
52100544403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2265241084.
The product of its (nonzero) digits is 9600, while the sum is 28.
The spelling of 52100544403 in words is "fifty-two billion, one hundred million, five hundred forty-four thousand, four hundred three".
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