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52104115433 = 55039468311
BaseRepresentation
bin110000100001101001…
…011011010011101001
311222111020002022101002
4300201221123103221
51323202123143213
635534124004345
73523121450036
oct604151332351
9158436068332
1052104115433
1120108462127
12a1216906b5
134bb496bb46
142743d6c38d
15154e471658
hexc21a5b4e9

52104115433 has 4 divisors (see below), whose sum is σ = 52113589248. Its totient is φ = 52094641620.

The previous prime is 52104115423. The next prime is 52104115487. The reversal of 52104115433 is 33451140125.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 52104115433 - 28 = 52104115177 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 52104115396 and 52104115405.

It is not an unprimeable number, because it can be changed into a prime (52104115423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4728653 + ... + 4739658.

It is an arithmetic number, because the mean of its divisors is an integer number (13028397312).

Almost surely, 252104115433 is an apocalyptic number.

It is an amenable number.

52104115433 is a deficient number, since it is larger than the sum of its proper divisors (9473815).

52104115433 is an equidigital number, since it uses as much as digits as its factorization.

52104115433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9473814.

The product of its (nonzero) digits is 7200, while the sum is 29.

Adding to 52104115433 its reverse (33451140125), we get a palindrome (85555255558).

The spelling of 52104115433 in words is "fifty-two billion, one hundred four million, one hundred fifteen thousand, four hundred thirty-three".

Divisors: 1 5503 9468311 52104115433