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52104431241 = 3246271125119
BaseRepresentation
bin110000100001101010…
…101000011010001001
311222111020200100120200
4300201222220122021
51323202213244431
635534134442413
73523124233542
oct604152503211
9158436610520
1052104431241
1120108658425
12a121803409
134bb4a4c805
1427440114c9
15154e4d4ee6
hexc21aa8689

52104431241 has 12 divisors (see below), whose sum is σ = 75264184320. Its totient is φ = 34735259160.

The previous prime is 52104431233. The next prime is 52104431243. The reversal of 52104431241 is 14213440125.

52104431241 is a `hidden beast` number, since 5 + 210 + 443 + 1 + 2 + 4 + 1 = 666.

It is not a de Polignac number, because 52104431241 - 23 = 52104431233 is a prime.

It is a super-3 number, since 3×521044312413 (a number of 33 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (52104431243) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 353880 + ... + 478998.

It is an arithmetic number, because the mean of its divisors is an integer number (6272015360).

Almost surely, 252104431241 is an apocalyptic number.

It is an amenable number.

52104431241 is a deficient number, since it is larger than the sum of its proper divisors (23159753079).

52104431241 is a wasteful number, since it uses less digits than its factorization.

52104431241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 171396 (or 171393 counting only the distinct ones).

The product of its (nonzero) digits is 3840, while the sum is 27.

Adding to 52104431241 its reverse (14213440125), we get a palindrome (66317871366).

The spelling of 52104431241 in words is "fifty-two billion, one hundred four million, four hundred thirty-one thousand, two hundred forty-one".

Divisors: 1 3 9 46271 125119 138813 375357 416439 1126071 5789381249 17368143747 52104431241