Base | Representation |
---|---|
bin | 1111001010100010011… |
… | …00011000000001011001 |
3 | 1211210221002121012010020 |
4 | 13211101030120001121 |
5 | 32014104112211213 |
6 | 1035211335141053 |
7 | 52434120322104 |
oct | 7452114300131 |
9 | 1753832535106 |
10 | 521053241433 |
11 | 190a82a7538a |
12 | 84b97814789 |
13 | 3a19aab449a |
14 | 1b30d35573b |
15 | d84909a923 |
hex | 7951318059 |
521053241433 has 16 divisors (see below), whose sum is σ = 696410395200. Its totient is φ = 346532854976.
The previous prime is 521053241399. The next prime is 521053241453. The reversal of 521053241433 is 334142350125.
It is a cyclic number.
It is not a de Polignac number, because 521053241433 - 213 = 521053233241 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 521053241394 and 521053241403.
It is not an unprimeable number, because it can be changed into a prime (521053241453) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5440243 + ... + 5535191.
It is an arithmetic number, because the mean of its divisors is an integer number (43525649700).
Almost surely, 2521053241433 is an apocalyptic number.
It is an amenable number.
521053241433 is a deficient number, since it is larger than the sum of its proper divisors (175357153767).
521053241433 is a wasteful number, since it uses less digits than its factorization.
521053241433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 99336.
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 521053241433 its reverse (334142350125), we get a palindrome (855195591558).
The spelling of 521053241433 in words is "five hundred twenty-one billion, fifty-three million, two hundred forty-one thousand, four hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •