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52111011097 = 431211883979
BaseRepresentation
bin110000100010000011…
…101110110100011001
311222111201001122110001
4300202003232310121
51323210404323342
635534531453001
73523234200025
oct604203566431
9158451048401
1052111011097
1120111341a22
12a123a57161
134bb6214712
142744c45385
15154ed848b7
hexc220eed19

52111011097 has 4 divisors (see below), whose sum is σ = 53322895120. Its totient is φ = 50899127076.

The previous prime is 52111011089. The next prime is 52111011109. The reversal of 52111011097 is 79011011125.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 52111011097 - 23 = 52111011089 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (52111011697) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 605941947 + ... + 605942032.

It is an arithmetic number, because the mean of its divisors is an integer number (13330723780).

Almost surely, 252111011097 is an apocalyptic number.

It is an amenable number.

52111011097 is a deficient number, since it is larger than the sum of its proper divisors (1211884023).

52111011097 is a wasteful number, since it uses less digits than its factorization.

52111011097 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1211884022.

The product of its (nonzero) digits is 630, while the sum is 28.

Adding to 52111011097 its sum of digits (28), we get a palindrome (52111011125).

The spelling of 52111011097 in words is "fifty-two billion, one hundred eleven million, eleven thousand, ninety-seven".

Divisors: 1 43 1211883979 52111011097