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52115131 = 139374929
BaseRepresentation
bin1100011011001…
…1011010111011
310122001201112001
43012303122323
5101320141011
65101001431
71201654105
oct306633273
9118051461
1052115131
1127465962
1215553277
13aa49073
146cc8575
1548967c1
hex31b36bb

52115131 has 4 divisors (see below), whose sum is σ = 52490200. Its totient is φ = 51740064.

The previous prime is 52115111. The next prime is 52115177. The reversal of 52115131 is 13151125.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-52115131 is a prime.

It is a super-2 number, since 2×521151312 = 5431973758294322, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 52115099 and 52115108.

It is not an unprimeable number, because it can be changed into a prime (52115111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 187326 + ... + 187603.

It is an arithmetic number, because the mean of its divisors is an integer number (13122550).

Almost surely, 252115131 is an apocalyptic number.

52115131 is a deficient number, since it is larger than the sum of its proper divisors (375069).

52115131 is a wasteful number, since it uses less digits than its factorization.

52115131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 375068.

The product of its digits is 150, while the sum is 19.

The square root of 52115131 is about 7219.0810356998. The cubic root of 52115131 is about 373.5263791331.

Adding to 52115131 its reverse (13151125), we get a palindrome (65266256).

The spelling of 52115131 in words is "fifty-two million, one hundred fifteen thousand, one hundred thirty-one".

Divisors: 1 139 374929 52115131