Base | Representation |
---|---|
bin | 110000100011001100… |
… | …001110110001110011 |
3 | 11222120000211012210002 |
4 | 300203030032301303 |
5 | 1323230241010441 |
6 | 35540451100215 |
7 | 3523554554006 |
oct | 604314166163 |
9 | 158500735702 |
10 | 52130016371 |
11 | 20121042964 |
12 | a12a2a166b |
13 | 4bba13a144 |
14 | 274759153d |
15 | 155188ab9b |
hex | c2330ec73 |
52130016371 has 4 divisors (see below), whose sum is σ = 52505052600. Its totient is φ = 51754980144.
The previous prime is 52130016271. The next prime is 52130016391. The reversal of 52130016371 is 17361003125.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 52130016371 - 230 = 51056274547 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (52130016391) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 187517906 + ... + 187518183.
It is an arithmetic number, because the mean of its divisors is an integer number (13126263150).
Almost surely, 252130016371 is an apocalyptic number.
52130016371 is a deficient number, since it is larger than the sum of its proper divisors (375036229).
52130016371 is a wasteful number, since it uses less digits than its factorization.
52130016371 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 375036228.
The product of its (nonzero) digits is 3780, while the sum is 29.
Adding to 52130016371 its reverse (17361003125), we get a palindrome (69491019496).
The spelling of 52130016371 in words is "fifty-two billion, one hundred thirty million, sixteen thousand, three hundred seventy-one".
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