Base | Representation |
---|---|
bin | 1111001011000001001… |
… | …11111011101011111001 |
3 | 1211211121010201202202011 |
4 | 13211200213323223321 |
5 | 32020121400424031 |
6 | 1035253144005521 |
7 | 52443412636531 |
oct | 7454047735371 |
9 | 1754533652664 |
10 | 521312123641 |
11 | 1910a6115421 |
12 | 8504a4608a1 |
13 | 3a20c616a1a |
14 | 1b3358a44c1 |
15 | d861b866b1 |
hex | 79609fbaf9 |
521312123641 has 4 divisors (see below), whose sum is σ = 521342872912. Its totient is φ = 521281374372.
The previous prime is 521312123621. The next prime is 521312123659. The reversal of 521312123641 is 146321213125.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 521312123641 - 217 = 521311992569 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (521312123611) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15349191 + ... + 15383116.
It is an arithmetic number, because the mean of its divisors is an integer number (130335718228).
Almost surely, 2521312123641 is an apocalyptic number.
It is an amenable number.
521312123641 is a deficient number, since it is larger than the sum of its proper divisors (30749271).
521312123641 is a wasteful number, since it uses less digits than its factorization.
521312123641 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30749270.
The product of its digits is 8640, while the sum is 31.
Adding to 521312123641 its reverse (146321213125), we get a palindrome (667633336766).
The spelling of 521312123641 in words is "five hundred twenty-one billion, three hundred twelve million, one hundred twenty-three thousand, six hundred forty-one".
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