Base | Representation |
---|---|
bin | 100101111011100111000… |
… | …1011001000000010001011 |
3 | 200110101022122210201010212 |
4 | 1023313032023020002023 |
5 | 1140403221103244120 |
6 | 15030534101231335 |
7 | 1045434205565621 |
oct | 113671613100213 |
9 | 20411278721125 |
10 | 5213254353035 |
11 | 172aa2419a333 |
12 | 70244440254b |
13 | 2ba7b938cc91 |
14 | 140473cc3511 |
15 | 9091e5db6c5 |
hex | 4bdce2c808b |
5213254353035 has 4 divisors (see below), whose sum is σ = 6255905223648. Its totient is φ = 4170603482424.
The previous prime is 5213254353017. The next prime is 5213254353071. The reversal of 5213254353035 is 5303534523125.
5213254353035 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5213254353035 is a prime.
It is a super-2 number, since 2×52132543530352 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5213254352983 and 5213254353001.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 521325435299 + ... + 521325435308.
It is an arithmetic number, because the mean of its divisors is an integer number (1563976305912).
Almost surely, 25213254353035 is an apocalyptic number.
5213254353035 is a deficient number, since it is larger than the sum of its proper divisors (1042650870613).
5213254353035 is a wasteful number, since it uses less digits than its factorization.
5213254353035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1042650870612.
The product of its (nonzero) digits is 810000, while the sum is 41.
The spelling of 5213254353035 in words is "five trillion, two hundred thirteen billion, two hundred fifty-four million, three hundred fifty-three thousand, thirty-five".
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