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52141253433 = 361328353047
BaseRepresentation
bin110000100011110111…
…000110001100111001
311222120210222010010120
4300203313012030321
51323241130102213
635541532003453
73524052225063
oct604367061471
9158523863116
1052141253433
1120127418495
12a132000589
134bbc572aa9
142748c78733
15155285a423
hexc23dc6339

52141253433 has 8 divisors (see below), whose sum is σ = 69635085888. Its totient is φ = 34704128304.

The previous prime is 52141253389. The next prime is 52141253441. The reversal of 52141253433 is 33435214125.

52141253433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 52141253433 - 216 = 52141187897 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 52141253394 and 52141253403.

It is not an unprimeable number, because it can be changed into a prime (52141253933) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14174685 + ... + 14178362.

It is an arithmetic number, because the mean of its divisors is an integer number (8704385736).

Almost surely, 252141253433 is an apocalyptic number.

It is an amenable number.

52141253433 is a deficient number, since it is larger than the sum of its proper divisors (17493832455).

52141253433 is a wasteful number, since it uses less digits than its factorization.

52141253433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28353663.

The product of its digits is 43200, while the sum is 33.

Adding to 52141253433 its reverse (33435214125), we get a palindrome (85576467558).

The spelling of 52141253433 in words is "fifty-two billion, one hundred forty-one million, two hundred fifty-three thousand, four hundred thirty-three".

Divisors: 1 3 613 1839 28353047 85059141 17380417811 52141253433