Base | Representation |
---|---|
bin | 1001101101100100… |
… | …10110010010001001 |
3 | 111110101022112011011 |
4 | 10312302112102021 |
5 | 41134304313213 |
6 | 2221221003521 |
7 | 243132264013 |
oct | 46662262211 |
9 | 14411275134 |
10 | 5214135433 |
11 | 2236275141 |
12 | 10162535a1 |
13 | 651324b50 |
14 | 3766c31b3 |
15 | 207b5403d |
hex | 136c96489 |
5214135433 has 16 divisors (see below), whose sum is σ = 5948416656. Its totient is φ = 4527728640.
The previous prime is 5214135431. The next prime is 5214135457. The reversal of 5214135433 is 3345314125.
It can be written as a sum of positive squares in 8 ways, for example, as 584285584 + 4629849849 = 24172^2 + 68043^2 .
It is a cyclic number.
It is not a de Polignac number, because 5214135433 - 21 = 5214135431 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5214135395 and 5214135404.
It is not an unprimeable number, because it can be changed into a prime (5214135431) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 590773 + ... + 599533.
It is an arithmetic number, because the mean of its divisors is an integer number (371776041).
Almost surely, 25214135433 is an apocalyptic number.
It is an amenable number.
5214135433 is a deficient number, since it is larger than the sum of its proper divisors (734281223).
5214135433 is a wasteful number, since it uses less digits than its factorization.
5214135433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11484.
The product of its digits is 21600, while the sum is 31.
The square root of 5214135433 is about 72208.9705853781. The cubic root of 5214135433 is about 1734.0466192018.
Adding to 5214135433 its reverse (3345314125), we get a palindrome (8559449558).
The spelling of 5214135433 in words is "five billion, two hundred fourteen million, one hundred thirty-five thousand, four hundred thirty-three".
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