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52143800424873 = 330895626826419
BaseRepresentation
bin10111101101100101011001…
…01100111001100110101001
320211121220021002212120200220
423312302230230321212221
523313311000402043443
6302522310424320253
713661156661364323
oct1366625454714651
9224556232776626
1052143800424873
1115684074a54513
125a21999313089
1323131a7001c41
14cc3ab8328613
156065a7310a83
hex2f6cacb399a9

52143800424873 has 8 divisors (see below), whose sum is σ = 69547574551200. Its totient is φ = 34751279957568.

The previous prime is 52143800424871. The next prime is 52143800424899. The reversal of 52143800424873 is 37842400834125.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 52143800424873 - 21 = 52143800424871 is a prime.

It is a super-3 number, since 3×521438004248733 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (52143800424871) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2813403943 + ... + 2813422476.

It is an arithmetic number, because the mean of its divisors is an integer number (8693446818900).

Almost surely, 252143800424873 is an apocalyptic number.

It is an amenable number.

52143800424873 is a deficient number, since it is larger than the sum of its proper divisors (17403774126327).

52143800424873 is a wasteful number, since it uses less digits than its factorization.

52143800424873 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5626829511.

The product of its (nonzero) digits is 5160960, while the sum is 51.

The spelling of 52143800424873 in words is "fifty-two trillion, one hundred forty-three billion, eight hundred million, four hundred twenty-four thousand, eight hundred seventy-three".

Divisors: 1 3 3089 9267 5626826419 16880479257 17381266808291 52143800424873