Base | Representation |
---|---|
bin | 10111101101111011001110… |
… | …10011111001010011100011 |
3 | 20211200000111221110210202121 |
4 | 23312331213103321103203 |
5 | 23314004001403102120 |
6 | 302531525440125111 |
7 | 13662053302014241 |
oct | 1366754723712343 |
9 | 224600457423677 |
10 | 52155521144035 |
11 | 15689039aa3281 |
12 | 5a2410a606797 |
13 | 231432434151a |
14 | cc44aac07791 |
15 | 606a412b65aa |
hex | 2f6f674f94e3 |
52155521144035 has 8 divisors (see below), whose sum is σ = 62586714108096. Its totient is φ = 41724357758400.
The previous prime is 52155521144009. The next prime is 52155521144057. The reversal of 52155521144035 is 53044112555125.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 52155521144035 - 25 = 52155521144003 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 52155521143982 and 52155521144000.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3310266 + ... + 10736335.
It is an arithmetic number, because the mean of its divisors is an integer number (7823339263512).
Almost surely, 252155521144035 is an apocalyptic number.
52155521144035 is a deficient number, since it is larger than the sum of its proper divisors (10431192964061).
52155521144035 is a wasteful number, since it uses less digits than its factorization.
52155521144035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14789213.
The product of its (nonzero) digits is 600000, while the sum is 43.
The spelling of 52155521144035 in words is "fifty-two trillion, one hundred fifty-five billion, five hundred twenty-one million, one hundred forty-four thousand, thirty-five".
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