Base | Representation |
---|---|
bin | 100101111110100010001… |
… | …1001000100000010000001 |
3 | 200110222112012121001002201 |
4 | 1023331010121010002001 |
5 | 1141004100331413231 |
6 | 15033453055513201 |
7 | 1046045612541004 |
oct | 113750431040201 |
9 | 20428465531081 |
10 | 5219532685441 |
11 | 17326561453a8 |
12 | 7036b6b28801 |
13 | 2bb27a00b379 |
14 | 1408aba6553b |
15 | 90b8a8a3161 |
hex | 4bf44644081 |
5219532685441 has 4 divisors (see below), whose sum is σ = 5387904707584. Its totient is φ = 5051160663300.
The previous prime is 5219532685333. The next prime is 5219532685517. The reversal of 5219532685441 is 1445862359125.
5219532685441 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5219532685441 - 215 = 5219532652673 is a prime.
It is not an unprimeable number, because it can be changed into a prime (5219532985441) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 84186011025 + ... + 84186011086.
It is an arithmetic number, because the mean of its divisors is an integer number (1346976176896).
Almost surely, 25219532685441 is an apocalyptic number.
It is an amenable number.
5219532685441 is a deficient number, since it is larger than the sum of its proper divisors (168372022143).
5219532685441 is a wasteful number, since it uses less digits than its factorization.
5219532685441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 168372022142.
The product of its digits is 10368000, while the sum is 55.
The spelling of 5219532685441 in words is "five trillion, two hundred nineteen billion, five hundred thirty-two million, six hundred eighty-five thousand, four hundred forty-one".
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