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52253513003011 = 146381356969231
BaseRepresentation
bin10111110000110001110000…
…00101001011000000000011
320212000101110011110000101211
423320120320011023000003
523322110143312044021
6303044533225510551
714002122523043215
oct1370307005130003
9225011404400354
1052253513003011
11157166549312a1
125a3b0b7942457
13232063cab6228
14cc91252905b5
156093790813e1
hex2f863814b003

52253513003011 has 4 divisors (see below), whose sum is σ = 52253870118624. Its totient is φ = 52253155887400.

The previous prime is 52253513002973. The next prime is 52253513003099. The reversal of 52253513003011 is 11030031535225.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 52253513003011 - 221 = 52253510905859 is a prime.

It is a super-2 number, since 2×522535130030112 (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (52253513003611) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 178338235 + ... + 178630996.

It is an arithmetic number, because the mean of its divisors is an integer number (13063467529656).

Almost surely, 252253513003011 is an apocalyptic number.

52253513003011 is a deficient number, since it is larger than the sum of its proper divisors (357115613).

52253513003011 is a wasteful number, since it uses less digits than its factorization.

52253513003011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 357115612.

The product of its (nonzero) digits is 13500, while the sum is 31.

Adding to 52253513003011 its reverse (11030031535225), we get a palindrome (63283544538236).

The spelling of 52253513003011 in words is "fifty-two trillion, two hundred fifty-three billion, five hundred thirteen million, three thousand, eleven".

Divisors: 1 146381 356969231 52253513003011