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52294903147 = 222967234541
BaseRepresentation
bin110000101101000001…
…001110010101101011
311222222112002022220201
4300231001032111223
51324044443400042
640005101133031
73530626225324
oct605501162553
9158875068821
1052294903147
11201a6122823
12a17555a177
134c1534bc96
14276143344b
1515610ab1b7
hexc2d04e56b

52294903147 has 4 divisors (see below), whose sum is σ = 52295360656. Its totient is φ = 52294445640.

The previous prime is 52294903123. The next prime is 52294903151. The reversal of 52294903147 is 74130949225.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 52294903147 - 27 = 52294903019 is a prime.

It is a super-2 number, since 2×522949031472 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 52294903097 and 52294903106.

It is not an unprimeable number, because it can be changed into a prime (52294943147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 105697 + ... + 340237.

It is an arithmetic number, because the mean of its divisors is an integer number (13073840164).

Almost surely, 252294903147 is an apocalyptic number.

52294903147 is a deficient number, since it is larger than the sum of its proper divisors (457509).

52294903147 is a wasteful number, since it uses less digits than its factorization.

52294903147 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 457508.

The product of its (nonzero) digits is 544320, while the sum is 46.

The spelling of 52294903147 in words is "fifty-two billion, two hundred ninety-four million, nine hundred three thousand, one hundred forty-seven".

Divisors: 1 222967 234541 52294903147