Search a number
-
+
523004435041 = 1147545857731
BaseRepresentation
bin1111001110001010111…
…11100101101001100001
31211222222002010002120011
413213011133211221201
532032103113410131
61040133120044521
752533352230154
oct7470537455141
91758862102504
10523004435041
11191894406a90
1285441163741
133a41c10080a
141b456547c9b
15d91051c0b1
hex79c57e5a61

523004435041 has 4 divisors (see below), whose sum is σ = 570550292784. Its totient is φ = 475458577300.

The previous prime is 523004435021. The next prime is 523004435081. The reversal of 523004435041 is 140534400325.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 523004435041 - 219 = 523003910753 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 523004434994 and 523004435012.

It is not an unprimeable number, because it can be changed into a prime (523004435021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23772928855 + ... + 23772928876.

It is an arithmetic number, because the mean of its divisors is an integer number (142637573196).

Almost surely, 2523004435041 is an apocalyptic number.

It is an amenable number.

523004435041 is a deficient number, since it is larger than the sum of its proper divisors (47545857743).

523004435041 is a wasteful number, since it uses less digits than its factorization.

523004435041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 47545857742.

The product of its (nonzero) digits is 28800, while the sum is 31.

Adding to 523004435041 its reverse (140534400325), we get a palindrome (663538835366).

The spelling of 523004435041 in words is "five hundred twenty-three billion, four million, four hundred thirty-five thousand, forty-one".

Divisors: 1 11 47545857731 523004435041