Base | Representation |
---|---|
bin | 10111110010011101010010… |
… | …00100001001010100101011 |
3 | 20212012220110110212112120201 |
4 | 23321032221010021110223 |
5 | 23324031411220244001 |
6 | 303131241530533031 |
7 | 14006235241052563 |
oct | 1371165104112453 |
9 | 225186413775521 |
10 | 52311243134251 |
11 | 15739089aa8362 |
12 | 5a4a329597177 |
13 | 2325c101babba |
14 | ccbc404b9da3 |
15 | 60ab073b5501 |
hex | 2f93a910952b |
52311243134251 has 4 divisors (see below), whose sum is σ = 52383198077392. Its totient is φ = 52239288191112.
The previous prime is 52311243134179. The next prime is 52311243134261. The reversal of 52311243134251 is 15243134211325.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 52311243134251 - 219 = 52311242609963 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 52311243134251.
It is not an unprimeable number, because it can be changed into a prime (52311243134261) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35977470480 + ... + 35977471933.
It is an arithmetic number, because the mean of its divisors is an integer number (13095799519348).
Almost surely, 252311243134251 is an apocalyptic number.
52311243134251 is a deficient number, since it is larger than the sum of its proper divisors (71954943141).
52311243134251 is an equidigital number, since it uses as much as digits as its factorization.
52311243134251 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 71954943140.
The product of its digits is 86400, while the sum is 37.
Adding to 52311243134251 its reverse (15243134211325), we get a palindrome (67554377345576).
The spelling of 52311243134251 in words is "fifty-two trillion, three hundred eleven billion, two hundred forty-three million, one hundred thirty-four thousand, two hundred fifty-one".
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