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52365403 = 56419283
BaseRepresentation
bin1100011111000…
…0100001011011
310122112102211101
43013300201123
5101401143103
65110212231
71204045546
oct307604133
9118472741
1052365403
11276169a2
1215654077
13ab05c5c
146d5185d
1548e5a1d
hex31f085b

52365403 has 4 divisors (see below), whose sum is σ = 52380328. Its totient is φ = 52350480.

The previous prime is 52365371. The next prime is 52365409. The reversal of 52365403 is 30456325.

52365403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 52365403 - 25 = 52365371 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (52365409) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1000 + ... + 10282.

It is an arithmetic number, because the mean of its divisors is an integer number (13095082).

Almost surely, 252365403 is an apocalyptic number.

52365403 is a deficient number, since it is larger than the sum of its proper divisors (14925).

52365403 is an equidigital number, since it uses as much as digits as its factorization.

52365403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14924.

The product of its (nonzero) digits is 10800, while the sum is 28.

The square root of 52365403 is about 7236.3943369609. The cubic root of 52365403 is about 374.1233519358.

The spelling of 52365403 in words is "fifty-two million, three hundred sixty-five thousand, four hundred three".

Divisors: 1 5641 9283 52365403