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5241100113 = 33254376333
BaseRepresentation
bin1001110000110010…
…01101011101010001
3111112021001110202000
410320121031131101
541213210200423
62224022544213
7243610421154
oct47031153521
914467043660
105241100113
11224a5120a7
121023298069
13656aa6392
1437a101c9b
1520a1cd843
hex13864d751

5241100113 has 16 divisors (see below), whose sum is σ = 7767747840. Its totient is φ = 3492646992.

The previous prime is 5241100097. The next prime is 5241100147. The reversal of 5241100113 is 3110011425.

It is not a de Polignac number, because 5241100113 - 24 = 5241100097 is a prime.

It is a super-2 number, since 2×52411001132 = 54938260788977225538, which contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (5241105113) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 30495 + ... + 106827.

It is an arithmetic number, because the mean of its divisors is an integer number (485484240).

Almost surely, 25241100113 is an apocalyptic number.

It is an amenable number.

5241100113 is a deficient number, since it is larger than the sum of its proper divisors (2526647727).

5241100113 is a wasteful number, since it uses less digits than its factorization.

5241100113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 78885 (or 78879 counting only the distinct ones).

The product of its (nonzero) digits is 120, while the sum is 18.

The square root of 5241100113 is about 72395.4426259001. The cubic root of 5241100113 is about 1737.0306639657.

Adding to 5241100113 its reverse (3110011425), we get a palindrome (8351111538).

The spelling of 5241100113 in words is "five billion, two hundred forty-one million, one hundred thousand, one hundred thirteen".

Divisors: 1 3 9 27 2543 7629 22887 68661 76333 228999 686997 2060991 194114819 582344457 1747033371 5241100113