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52433135403643 = 156413352287923
BaseRepresentation
bin10111110110000000010100…
…11010010000001001111011
320212122120002100200101200201
423323000022122100021323
523333031030130404033
6303303241101143031
714021111655206431
oct1373001232201173
9225576070611621
1052433135403643
111578584a008485
125a69a86b5aa77
1323345674301a7
14cd3ac4c76d51
1560dd8d54d47d
hex2fb00a69027b

52433135403643 has 4 divisors (see below), whose sum is σ = 52436487707208. Its totient is φ = 52429783100080.

The previous prime is 52433135403631. The next prime is 52433135403731. The reversal of 52433135403643 is 34630453133425.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-52433135403643 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 52433135403593 and 52433135403602.

It is not an unprimeable number, because it can be changed into a prime (52433135403613) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1676128321 + ... + 1676159602.

It is an arithmetic number, because the mean of its divisors is an integer number (13109121926802).

Almost surely, 252433135403643 is an apocalyptic number.

52433135403643 is a deficient number, since it is larger than the sum of its proper divisors (3352303565).

52433135403643 is a wasteful number, since it uses less digits than its factorization.

52433135403643 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3352303564.

The product of its (nonzero) digits is 4665600, while the sum is 46.

The spelling of 52433135403643 in words is "fifty-two trillion, four hundred thirty-three billion, one hundred thirty-five million, four hundred three thousand, six hundred forty-three".

Divisors: 1 15641 3352287923 52433135403643