Base | Representation |
---|---|
bin | 10111110110000000010100… |
… | …11010010000001001111011 |
3 | 20212122120002100200101200201 |
4 | 23323000022122100021323 |
5 | 23333031030130404033 |
6 | 303303241101143031 |
7 | 14021111655206431 |
oct | 1373001232201173 |
9 | 225576070611621 |
10 | 52433135403643 |
11 | 1578584a008485 |
12 | 5a69a86b5aa77 |
13 | 23345674301a7 |
14 | cd3ac4c76d51 |
15 | 60dd8d54d47d |
hex | 2fb00a69027b |
52433135403643 has 4 divisors (see below), whose sum is σ = 52436487707208. Its totient is φ = 52429783100080.
The previous prime is 52433135403631. The next prime is 52433135403731. The reversal of 52433135403643 is 34630453133425.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-52433135403643 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 52433135403593 and 52433135403602.
It is not an unprimeable number, because it can be changed into a prime (52433135403613) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1676128321 + ... + 1676159602.
It is an arithmetic number, because the mean of its divisors is an integer number (13109121926802).
Almost surely, 252433135403643 is an apocalyptic number.
52433135403643 is a deficient number, since it is larger than the sum of its proper divisors (3352303565).
52433135403643 is a wasteful number, since it uses less digits than its factorization.
52433135403643 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3352303564.
The product of its (nonzero) digits is 4665600, while the sum is 46.
The spelling of 52433135403643 in words is "fifty-two trillion, four hundred thirty-three billion, one hundred thirty-five million, four hundred three thousand, six hundred forty-three".
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