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5251251045105 = 325132910123912823
BaseRepresentation
bin100110001101010011011…
…1101000000001011110001
3200121000101201021122210100
41030122212331000023301
51142014030231420410
615100220314223013
71051250616256542
oct114324675001361
920530351248710
105251251045105
11174505235148a
12709889424a69
132c12633aa620
1414223a3b44c9
15918e52aa8c0
hex4c6a6f402f1

5251251045105 has 192 divisors, whose sum is σ = 10284396595200. Its totient is φ = 2460839270400.

The previous prime is 5251251045091. The next prime is 5251251045109. The reversal of 5251251045105 is 5015401521525.

5251251045105 is a `hidden beast` number, since 5 + 2 + 5 + 125 + 10 + 4 + 510 + 5 = 666.

It is not a de Polignac number, because 5251251045105 - 28 = 5251251044849 is a prime.

It is a super-3 number, since 3×52512510451053 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 5251251045105.

It is not an unprimeable number, because it can be changed into a prime (5251251045109) by changing a digit.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 409511724 + ... + 409524546.

It is an arithmetic number, because the mean of its divisors is an integer number (53564565600).

Almost surely, 25251251045105 is an apocalyptic number.

It is an amenable number.

5251251045105 is a deficient number, since it is larger than the sum of its proper divisors (5033145550095).

5251251045105 is a wasteful number, since it uses less digits than its factorization.

5251251045105 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13216 (or 13213 counting only the distinct ones).

The product of its (nonzero) digits is 50000, while the sum is 36.

The spelling of 5251251045105 in words is "five trillion, two hundred fifty-one billion, two hundred fifty-one million, forty-five thousand, one hundred five".