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52513176732001 = 111227472126163
BaseRepresentation
bin10111111000010101011010…
…01111101100000101100001
320212221012200120120011112121
423330022231033230011201
523340333441220411001
6303404115332424241
714026644321241036
oct1374125517540541
9225835616504477
1052513176732001
1115806793282127
125a814a4778081
13233bc81ca534b
14cd79192cd38d
15610ec54826a1
hex2fc2ad3ec161

52513176732001 has 4 divisors (see below), whose sum is σ = 52513648969392. Its totient is φ = 52512704494612.

The previous prime is 52513176731969. The next prime is 52513176732011. The reversal of 52513176732001 is 10023767131525.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 52513176732001 - 25 = 52513176731969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (52513176732011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 235951855 + ... + 236174308.

It is an arithmetic number, because the mean of its divisors is an integer number (13128412242348).

Almost surely, 252513176732001 is an apocalyptic number.

It is an amenable number.

52513176732001 is a deficient number, since it is larger than the sum of its proper divisors (472237391).

52513176732001 is a wasteful number, since it uses less digits than its factorization.

52513176732001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 472237390.

The product of its (nonzero) digits is 264600, while the sum is 43.

The spelling of 52513176732001 in words is "fifty-two trillion, five hundred thirteen billion, one hundred seventy-six million, seven hundred thirty-two thousand, one".

Divisors: 1 111227 472126163 52513176732001