Base | Representation |
---|---|
bin | 10111111000010101011010… |
… | …01111101100000101100001 |
3 | 20212221012200120120011112121 |
4 | 23330022231033230011201 |
5 | 23340333441220411001 |
6 | 303404115332424241 |
7 | 14026644321241036 |
oct | 1374125517540541 |
9 | 225835616504477 |
10 | 52513176732001 |
11 | 15806793282127 |
12 | 5a814a4778081 |
13 | 233bc81ca534b |
14 | cd79192cd38d |
15 | 610ec54826a1 |
hex | 2fc2ad3ec161 |
52513176732001 has 4 divisors (see below), whose sum is σ = 52513648969392. Its totient is φ = 52512704494612.
The previous prime is 52513176731969. The next prime is 52513176732011. The reversal of 52513176732001 is 10023767131525.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 52513176732001 - 25 = 52513176731969 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (52513176732011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 235951855 + ... + 236174308.
It is an arithmetic number, because the mean of its divisors is an integer number (13128412242348).
Almost surely, 252513176732001 is an apocalyptic number.
It is an amenable number.
52513176732001 is a deficient number, since it is larger than the sum of its proper divisors (472237391).
52513176732001 is a wasteful number, since it uses less digits than its factorization.
52513176732001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 472237390.
The product of its (nonzero) digits is 264600, while the sum is 43.
The spelling of 52513176732001 in words is "fifty-two trillion, five hundred thirteen billion, one hundred seventy-six million, seven hundred thirty-two thousand, one".
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