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52514334501305 = 510502866900261
BaseRepresentation
bin10111111000010111100100…
…10000001110100110111001
320212221022200021002221110012
423330023302100032212321
523340343324113020210
6303404430251431305
714030015110150535
oct1374136220164671
9225838607087405
1052514334501305
1115807227864366
125a81768455535
13233c107b01841
14cd79c8d88bc5
15611041e2a305
hex2fc2f240e9b9

52514334501305 has 4 divisors (see below), whose sum is σ = 63017201401572. Its totient is φ = 42011467601040.

The previous prime is 52514334501259. The next prime is 52514334501319. The reversal of 52514334501305 is 50310543341525.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 34886789502016 + 17627544999289 = 5906504^2 + 4198517^2 .

It is not a de Polignac number, because 52514334501305 - 216 = 52514334435769 is a prime.

It is a super-2 number, since 2×525143345013052 (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5251433450126 + ... + 5251433450135.

It is an arithmetic number, because the mean of its divisors is an integer number (15754300350393).

Almost surely, 252514334501305 is an apocalyptic number.

It is an amenable number.

52514334501305 is a deficient number, since it is larger than the sum of its proper divisors (10502866900267).

52514334501305 is a wasteful number, since it uses less digits than its factorization.

52514334501305 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10502866900266.

The product of its (nonzero) digits is 540000, while the sum is 41.

The spelling of 52514334501305 in words is "fifty-two trillion, five hundred fourteen billion, three hundred thirty-four million, five hundred one thousand, three hundred five".

Divisors: 1 5 10502866900261 52514334501305