52521311450121 has 4 divisors (see below), whose sum is σ = 70028415266832. Its totient is φ = 35014207633412.

The previous prime is 52521311450107. The next prime is 52521311450131. The reversal of 52521311450121 is 12105411312525.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 52521311450121 - 2⁵ = 52521311450089 is a prime.

It is a super-3 number, since 3×52521311450121³ (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (52521311450131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8753551908351 + ... + 8753551908356.

It is an arithmetic number, because the mean of its divisors is an integer number (17507103816708).

Almost surely, 2^{52521311450121} is an apocalyptic number.

It is an amenable number.

52521311450121 is a deficient number, since it is larger than the sum of its proper divisors (17507103816711).

52521311450121 is a wasteful number, since it uses less digits than its factorization.

52521311450121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17507103816710.

The product of its (nonzero) digits is 12000, while the sum is 33.

Adding to 52521311450121 its reverse (12105411312525), we get a palindrome (64626722762646).

The spelling of 52521311450121 in words is "fifty-two trillion, five hundred twenty-one billion, three hundred eleven million, four hundred fifty thousand, one hundred twenty-one".