Base | Representation |
---|---|
bin | 111011101101101001100010… |
… | …0110111110000001110001001 |
3 | 2112212201210010200002001012021 |
4 | 1313123103010313300032021 |
5 | 1022321042033014342301 |
6 | 5101033301251444441 |
7 | 215430405113450641 |
oct | 16733230467601611 |
9 | 2485653120061167 |
10 | 525243443512201 |
11 | 1423a4547881257 |
12 | 4aaab8465b6721 |
13 | 1971032365c58b |
14 | 939bcbdba5521 |
15 | 40acbc23b18a1 |
hex | 1ddb4c4df0389 |
525243443512201 has 16 divisors (see below), whose sum is σ = 539612201317248. Its totient is φ = 510883801084800.
The previous prime is 525243443512163. The next prime is 525243443512321. The reversal of 525243443512201 is 102215344342525.
It is a cyclic number.
It is not a de Polignac number, because 525243443512201 - 213 = 525243443504009 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (525243443572201) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4896271101 + ... + 4896378373.
It is an arithmetic number, because the mean of its divisors is an integer number (33725762582328).
Almost surely, 2525243443512201 is an apocalyptic number.
It is an amenable number.
525243443512201 is a deficient number, since it is larger than the sum of its proper divisors (14368757805047).
525243443512201 is a wasteful number, since it uses less digits than its factorization.
525243443512201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 148512.
The product of its (nonzero) digits is 1152000, while the sum is 43.
Adding to 525243443512201 its reverse (102215344342525), we get a palindrome (627458787854726).
The spelling of 525243443512201 in words is "five hundred twenty-five trillion, two hundred forty-three billion, four hundred forty-three million, five hundred twelve thousand, two hundred one".
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