Base | Representation |
---|---|
bin | 10111111000101011100001… |
… | …11110101000000100111001 |
3 | 20212222100100002012111121220 |
4 | 23330111300332220010321 |
5 | 23341032300413344212 |
6 | 303413401453222253 |
7 | 14030544500654202 |
oct | 1374256076500471 |
9 | 225870302174556 |
10 | 52525050528057 |
11 | 15810826774918 |
12 | 5a83859191989 |
13 | 2340124c50183 |
14 | cd83242585a9 |
15 | 61146cac438c |
hex | 2fc570fa8139 |
52525050528057 has 16 divisors (see below), whose sum is σ = 72310495137792. Its totient is φ = 33878714150160.
The previous prime is 52525050528053. The next prime is 52525050528061. The reversal of 52525050528057 is 75082505052525.
It is an interprime number because it is at equal distance from previous prime (52525050528053) and next prime (52525050528061).
It is not a de Polignac number, because 52525050528057 - 22 = 52525050528053 is a prime.
It is not an unprimeable number, because it can be changed into a prime (52525050528053) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 69750333 + ... + 70499354.
It is an arithmetic number, because the mean of its divisors is an integer number (4519405946112).
Almost surely, 252525050528057 is an apocalyptic number.
It is an amenable number.
52525050528057 is a deficient number, since it is larger than the sum of its proper divisors (19785444609735).
52525050528057 is a wasteful number, since it uses less digits than its factorization.
52525050528057 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 140253748.
The product of its (nonzero) digits is 7000000, while the sum is 51.
The spelling of 52525050528057 in words is "fifty-two trillion, five hundred twenty-five billion, fifty million, five hundred twenty-eight thousand, fifty-seven".
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