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5253171130563 = 31751057043521
BaseRepresentation
bin100110001110001100101…
…1001100011000011000011
3200121012100112021002212120
41030130121121203003003
51142031443302134223
615101135024255323
71051346322602406
oct114343131430303
920535315232776
105253171130563
111745948176074
1270a124471543
132c14ab124475
1414237d3c9d3d
15919a8b34be3
hex4c7196630c3

5253171130563 has 4 divisors (see below), whose sum is σ = 7004228174088. Its totient is φ = 3502114087040.

The previous prime is 5253171130513. The next prime is 5253171130567. The reversal of 5253171130563 is 3650311713525.

5253171130563 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5253171130563 - 217 = 5253170999491 is a prime.

It is not an unprimeable number, because it can be changed into a prime (5253171130567) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 875528521758 + ... + 875528521763.

It is an arithmetic number, because the mean of its divisors is an integer number (1751057043522).

Almost surely, 25253171130563 is an apocalyptic number.

5253171130563 is a deficient number, since it is larger than the sum of its proper divisors (1751057043525).

5253171130563 is a wasteful number, since it uses less digits than its factorization.

5253171130563 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1751057043524.

The product of its (nonzero) digits is 283500, while the sum is 42.

The spelling of 5253171130563 in words is "five trillion, two hundred fifty-three billion, one hundred seventy-one million, one hundred thirty thousand, five hundred sixty-three".

Divisors: 1 3 1751057043521 5253171130563