Base | Representation |
---|---|
bin | 110000111011010110… |
… | …101001111101011011 |
3 | 12000121021121221202220 |
4 | 300323112221331123 |
5 | 1330043030333311 |
6 | 40045011555123 |
7 | 3536606360166 |
oct | 607326517533 |
9 | 160537557686 |
10 | 52535402331 |
11 | 20309957385 |
12 | a221bbbaa3 |
13 | 4c531160a9 |
14 | 2785358add |
15 | 1577265206 |
hex | c3b5a9f5b |
52535402331 has 4 divisors (see below), whose sum is σ = 70047203112. Its totient is φ = 35023601552.
The previous prime is 52535402327. The next prime is 52535402333. The reversal of 52535402331 is 13320453525.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 52535402331 - 22 = 52535402327 is a prime.
It is a super-2 number, since 2×525354023312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 52535402292 and 52535402301.
It is not an unprimeable number, because it can be changed into a prime (52535402333) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8755900386 + ... + 8755900391.
It is an arithmetic number, because the mean of its divisors is an integer number (17511800778).
Almost surely, 252535402331 is an apocalyptic number.
52535402331 is a deficient number, since it is larger than the sum of its proper divisors (17511800781).
52535402331 is a wasteful number, since it uses less digits than its factorization.
52535402331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17511800780.
The product of its (nonzero) digits is 54000, while the sum is 33.
Adding to 52535402331 its reverse (13320453525), we get a palindrome (65855855856).
The spelling of 52535402331 in words is "fifty-two billion, five hundred thirty-five million, four hundred two thousand, three hundred thirty-one".
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