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52540433 = 114776403
BaseRepresentation
bin1100100001101…
…1010000010001
310122212022220222
43020123100101
5101422243213
65114042425
71205405051
oct310332021
9118768828
1052540433
1127726450
1215719415
13ab6781a
146d99561
15492c808
hex321b411

52540433 has 4 divisors (see below), whose sum is σ = 57316848. Its totient is φ = 47764020.

The previous prime is 52540429. The next prime is 52540457. The reversal of 52540433 is 33404525.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 52540433 - 22 = 52540429 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (52540483) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2388191 + ... + 2388212.

It is an arithmetic number, because the mean of its divisors is an integer number (14329212).

Almost surely, 252540433 is an apocalyptic number.

It is an amenable number.

52540433 is a deficient number, since it is larger than the sum of its proper divisors (4776415).

52540433 is a wasteful number, since it uses less digits than its factorization.

52540433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4776414.

The product of its (nonzero) digits is 7200, while the sum is 26.

The square root of 52540433 is about 7248.4779781689. The cubic root of 52540433 is about 374.5397209092.

Adding to 52540433 its reverse (33404525), we get a palindrome (85944958).

The spelling of 52540433 in words is "fifty-two million, five hundred forty thousand, four hundred thirty-three".

Divisors: 1 11 4776403 52540433