525413505005035 has 4 divisors (see below), whose sum is σ = 630496206006048. Its totient is φ = 420330804004024.

The previous prime is 525413505005009. The next prime is 525413505005063. The reversal of 525413505005035 is 530500505314525.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 525413505005035 - 2⁷ = 525413505004907 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 525413505004982 and 525413505005000.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52541350500499 + ... + 52541350500508.

It is an arithmetic number, because the mean of its divisors is an integer number (157624051501512).

Almost surely, 2^{525413505005035} is an apocalyptic number.

525413505005035 is a deficient number, since it is larger than the sum of its proper divisors (105082701001013).

525413505005035 is a wasteful number, since it uses less digits than its factorization.

525413505005035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 105082701001012.

The product of its (nonzero) digits is 1125000, while the sum is 43.

The spelling of 525413505005035 in words is "five hundred twenty-five trillion, four hundred thirteen billion, five hundred five million, five thousand, thirty-five".