Base | Representation |
---|---|
bin | 10111111001001110111000… |
… | …11100101001110111011001 |
3 | 20220001011100000212220000022 |
4 | 23330213130130221313121 |
5 | 23341340140024243001 |
6 | 303430221250520225 |
7 | 14032116062661440 |
oct | 1374473434516731 |
9 | 226034300786008 |
10 | 52544033431001 |
11 | 15818888062862 |
12 | 5a87476596075 |
13 | 2341b5b9b2918 |
14 | cd9205421d57 |
15 | 611bce3d311b |
hex | 2fc9dc729dd9 |
52544033431001 has 8 divisors (see below), whose sum is σ = 60773821800384. Its totient is φ = 44495119531440.
The previous prime is 52544033430949. The next prime is 52544033431061. The reversal of 52544033431001 is 10013433044525.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 52544033431001 - 26 = 52544033430937 is a prime.
It is not an unprimeable number, because it can be changed into a prime (52544033431061) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 45218616830 + ... + 45218617991.
It is an arithmetic number, because the mean of its divisors is an integer number (7596727725048).
Almost surely, 252544033431001 is an apocalyptic number.
It is an amenable number.
52544033431001 is a deficient number, since it is larger than the sum of its proper divisors (8229788369383).
52544033431001 is an equidigital number, since it uses as much as digits as its factorization.
52544033431001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 90437234911.
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 52544033431001 its reverse (10013433044525), we get a palindrome (62557466475526).
The spelling of 52544033431001 in words is "fifty-two trillion, five hundred forty-four billion, thirty-three million, four hundred thirty-one thousand, one".
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