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52580136907081 = 77511448129583
BaseRepresentation
bin10111111010010010001000…
…11000011111000101001001
320220011121112010221111120001
423331021010120133011021
523342433110022011311
6303454551553403001
714034534544316260
oct1375110430370511
9226147463844501
1052580136907081
11158321245827a3
125a92471569461
132345393703514
14cdac6c2d35d7
15612ae3c844c1
hex2fd24461f149

52580136907081 has 4 divisors (see below), whose sum is σ = 60091585036672. Its totient is φ = 45068688777492.

The previous prime is 52580136907043. The next prime is 52580136907099. The reversal of 52580136907081 is 18070963108525.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-52580136907081 is a prime.

It is a super-2 number, since 2×525801369070812 (a number of 28 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (52580136907981) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3755724064785 + ... + 3755724064798.

It is an arithmetic number, because the mean of its divisors is an integer number (15022896259168).

Almost surely, 252580136907081 is an apocalyptic number.

It is an amenable number.

52580136907081 is a deficient number, since it is larger than the sum of its proper divisors (7511448129591).

52580136907081 is an equidigital number, since it uses as much as digits as its factorization.

52580136907081 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7511448129590.

The product of its (nonzero) digits is 3628800, while the sum is 55.

The spelling of 52580136907081 in words is "fifty-two trillion, five hundred eighty billion, one hundred thirty-six million, nine hundred seven thousand, eighty-one".

Divisors: 1 7 7511448129583 52580136907081