Base | Representation |
---|---|
bin | 110000111111000011… |
… | …001101010111010011 |
3 | 12000202121022102212121 |
4 | 300333003031113103 |
5 | 1330204414211311 |
6 | 40055105035111 |
7 | 3541261431241 |
oct | 607703152723 |
9 | 160677272777 |
10 | 52597413331 |
11 | 20340961141 |
12 | a23a925a97 |
13 | 4c62c184a8 |
14 | 278d69b791 |
15 | 157c913b71 |
hex | c3f0cd5d3 |
52597413331 has 4 divisors (see below), whose sum is σ = 52649542600. Its totient is φ = 52545284064.
The previous prime is 52597413329. The next prime is 52597413359. The reversal of 52597413331 is 13331479525.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 52597413331 - 21 = 52597413329 is a prime.
It is a super-2 number, since 2×525974133312 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (52597413371) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26063121 + ... + 26065138.
It is an arithmetic number, because the mean of its divisors is an integer number (13162385650).
Almost surely, 252597413331 is an apocalyptic number.
52597413331 is a deficient number, since it is larger than the sum of its proper divisors (52129269).
52597413331 is a wasteful number, since it uses less digits than its factorization.
52597413331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52129268.
The product of its digits is 340200, while the sum is 43.
The spelling of 52597413331 in words is "fifty-two billion, five hundred ninety-seven million, four hundred thirteen thousand, three hundred thirty-one".
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