Base | Representation |
---|---|
bin | 1001110011000001… |
… | …00110000010101011 |
3 | 111120120021012001012 |
4 | 10321200212002223 |
5 | 41233003004120 |
6 | 2225532014135 |
7 | 244225446611 |
oct | 47140460253 |
9 | 14516235035 |
10 | 5259813035 |
11 | 225a033424 |
12 | 102960134b |
13 | 65a928a09 |
14 | 37c7b36b1 |
15 | 20bb781c5 |
hex | 1398260ab |
5259813035 has 8 divisors (see below), whose sum is σ = 6643974480. Its totient is φ = 3986384544.
The previous prime is 5259812989. The next prime is 5259813037. The reversal of 5259813035 is 5303189525.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5259813035 - 216 = 5259747499 is a prime.
It is a super-2 number, since 2×52598130352 = 55331266326311822450, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5259812983 and 5259813001.
It is not an unprimeable number, because it can be changed into a prime (5259813037) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 27683132 + ... + 27683321.
It is an arithmetic number, because the mean of its divisors is an integer number (830496810).
Almost surely, 25259813035 is an apocalyptic number.
5259813035 is a deficient number, since it is larger than the sum of its proper divisors (1384161445).
5259813035 is a wasteful number, since it uses less digits than its factorization.
5259813035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55366477.
The product of its (nonzero) digits is 162000, while the sum is 41.
The square root of 5259813035 is about 72524.5684923392. The cubic root of 5259813035 is about 1739.0955173863.
The spelling of 5259813035 in words is "five billion, two hundred fifty-nine million, eight hundred thirteen thousand, thirty-five".
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