Base | Representation |
---|---|
bin | 100110010011110101001… |
… | …1000000100110000111011 |
3 | 200122100120111222220000111 |
4 | 1030213222120010300323 |
5 | 1142231231340221430 |
6 | 15110455203245151 |
7 | 1052255141024335 |
oct | 114475230046073 |
9 | 20570514886014 |
10 | 5265267117115 |
11 | 174aa95027875 |
12 | 71053b3797b7 |
13 | 2c2688125a65 |
14 | 142ba9a72455 |
15 | 91e65a15c2a |
hex | 4c9ea604c3b |
5265267117115 has 8 divisors (see below), whose sum is σ = 6319736278848. Its totient is φ = 4211269868160.
The previous prime is 5265267117083. The next prime is 5265267117151. The reversal of 5265267117115 is 5117117625625.
5265267117115 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 5265267117115 - 25 = 5265267117083 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 117953646 + ... + 117998275.
It is an arithmetic number, because the mean of its divisors is an integer number (789967034856).
Almost surely, 25265267117115 is an apocalyptic number.
5265267117115 is a deficient number, since it is larger than the sum of its proper divisors (1054469161733).
5265267117115 is a wasteful number, since it uses less digits than its factorization.
5265267117115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 235956389.
The product of its digits is 882000, while the sum is 49.
The spelling of 5265267117115 in words is "five trillion, two hundred sixty-five billion, two hundred sixty-seven million, one hundred seventeen thousand, one hundred fifteen".
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