Base | Representation |
---|---|
bin | 110001000100110101… |
… | …001001101001101011 |
3 | 12001000100210102210001 |
4 | 301010311021221223 |
5 | 1330404231011103 |
6 | 40112451403431 |
7 | 3543546636163 |
oct | 610465115153 |
9 | 161010712701 |
10 | 52694391403 |
11 | 20390679205 |
12 | a2672b3577 |
13 | 4c7a041674 |
14 | 279c5035a3 |
15 | 15861bd01d |
hex | c44d49a6b |
52694391403 has 4 divisors (see below), whose sum is σ = 52694881600. Its totient is φ = 52693901208.
The previous prime is 52694391371. The next prime is 52694391457. The reversal of 52694391403 is 30419349625.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 52694391403 - 25 = 52694391371 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (52694391493) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6300 + ... + 324697.
It is an arithmetic number, because the mean of its divisors is an integer number (13173720400).
Almost surely, 252694391403 is an apocalyptic number.
52694391403 is a deficient number, since it is larger than the sum of its proper divisors (490197).
52694391403 is a wasteful number, since it uses less digits than its factorization.
52694391403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 490196.
The product of its (nonzero) digits is 699840, while the sum is 46.
The spelling of 52694391403 in words is "fifty-two billion, six hundred ninety-four million, three hundred ninety-one thousand, four hundred three".
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