Base | Representation |
---|---|
bin | 110001000111110001… |
… | …011101010010010011 |
3 | 12001010210200100202200 |
4 | 301013301131102103 |
5 | 1331004400124044 |
6 | 40121413414243 |
7 | 3545016343113 |
oct | 610761352223 |
9 | 161123610680 |
10 | 52743754899 |
11 | 20406524790 |
12 | a27b93a383 |
13 | 4c87336134 |
14 | 27a4cb3043 |
15 | 158a6be369 |
hex | c47c5d493 |
52743754899 has 12 divisors (see below), whose sum is σ = 83111371512. Its totient is φ = 31965912000.
The previous prime is 52743754883. The next prime is 52743754933. The reversal of 52743754899 is 99845734725.
52743754899 is a `hidden beast` number, since 52 + 7 + 4 + 37 + 548 + 9 + 9 = 666.
52743754899 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 52743754899 - 24 = 52743754883 is a prime.
It is not an unprimeable number, because it can be changed into a prime (52743754829) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 266382502 + ... + 266382699.
It is an arithmetic number, because the mean of its divisors is an integer number (6925947626).
Almost surely, 252743754899 is an apocalyptic number.
52743754899 is a deficient number, since it is larger than the sum of its proper divisors (30367616613).
52743754899 is a wasteful number, since it uses less digits than its factorization.
52743754899 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 532765218 (or 532765215 counting only the distinct ones).
The product of its digits is 76204800, while the sum is 63.
The spelling of 52743754899 in words is "fifty-two billion, seven hundred forty-three million, seven hundred fifty-four thousand, eight hundred ninety-nine".
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