Base | Representation |
---|---|
bin | 110001001110011000… |
… | …111011001110010001 |
3 | 12001102112120020012220 |
4 | 301032120323032101 |
5 | 1331221304430213 |
6 | 40140421011253 |
7 | 3550535041062 |
oct | 611630731621 |
9 | 161375506186 |
10 | 52854764433 |
11 | 204631558a9 |
12 | a2b0b53b29 |
13 | 4ca4332b53 |
14 | 27b592c569 |
15 | 15952eae23 |
hex | c4e63b391 |
52854764433 has 16 divisors (see below), whose sum is σ = 74272327680. Its totient is φ = 33341365584.
The previous prime is 52854764411. The next prime is 52854764441. The reversal of 52854764433 is 33446745825.
52854764433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 52854764433 - 214 = 52854748049 is a prime.
It is a super-2 number, since 2×528547644332 (a number of 22 digits) contains 22 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (52854760433) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 516441 + ... + 610262.
It is an arithmetic number, because the mean of its divisors is an integer number (4642020480).
Almost surely, 252854764433 is an apocalyptic number.
It is an amenable number.
52854764433 is a deficient number, since it is larger than the sum of its proper divisors (21417563247).
52854764433 is a wasteful number, since it uses less digits than its factorization.
52854764433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1127548.
The product of its digits is 9676800, while the sum is 51.
The spelling of 52854764433 in words is "fifty-two billion, eight hundred fifty-four million, seven hundred sixty-four thousand, four hundred thirty-three".
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