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5299431339035 = 51059886267807
BaseRepresentation
bin100110100011101111010…
…1110001111010000011011
3200202121202111000011222002
41031013132232033100123
51143311213410322120
615134305233151215
71054604564102021
oct115073656172033
920677674004862
105299431339035
111763526920419
127170949bb50b
132c597114a8a2
141446cb17c711
1592cb5003375
hex4d1deb8f41b

5299431339035 has 4 divisors (see below), whose sum is σ = 6359317606848. Its totient is φ = 4239545071224.

The previous prime is 5299431339001. The next prime is 5299431339067. The reversal of 5299431339035 is 5309331349925.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5299431339035 - 220 = 5299430290459 is a prime.

It is a super-4 number, since 4×52994313390354 (a number of 52 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 529943133899 + ... + 529943133908.

It is an arithmetic number, because the mean of its divisors is an integer number (1589829401712).

Almost surely, 25299431339035 is an apocalyptic number.

5299431339035 is a deficient number, since it is larger than the sum of its proper divisors (1059886267813).

5299431339035 is a wasteful number, since it uses less digits than its factorization.

5299431339035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1059886267812.

The product of its (nonzero) digits is 11809800, while the sum is 56.

The spelling of 5299431339035 in words is "five trillion, two hundred ninety-nine billion, four hundred thirty-one million, three hundred thirty-nine thousand, thirty-five".

Divisors: 1 5 1059886267807 5299431339035