53000113 has 4 divisors (see below), whose sum is σ = 53898480. Its totient is φ = 52101748.

The previous prime is 53000099. The next prime is 53000137. The reversal of 53000113 is 31100035.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-53000113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 53000093 and 53000102.

It is not an unprimeable number, because it can be changed into a prime (53000153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 449095 + ... + 449212.

It is an arithmetic number, because the mean of its divisors is an integer number (13474620).

Almost surely, 2^53000113 is an apocalyptic number.

It is an amenable number.

53000113 is a deficient number, since it is larger than the sum of its proper divisors (898367).

53000113 is an equidigital number, since it uses as much as digits as its factorization.

53000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 898366.

The product of its (nonzero) digits is 45, while the sum is 13.

The square root of 53000113 is about 7280.1176501482. The cubic root of 53000113 is about 375.6288423781.

Adding to 53000113 its reverse (31100035), we get a palindrome (84100148).

The spelling of 53000113 in words is "fifty-three million, one hundred thirteen", and thus it is an aban number.