Base | Representation |
---|---|
bin | 111100010000010001000000… |
… | …1110111010100010111011011 |
3 | 2120111120121120221012022200120 |
4 | 1320200202001313110113123 |
5 | 1023432014320112313403 |
6 | 5115115055221204323 |
7 | 216431214255551004 |
oct | 17040420167242733 |
9 | 2514517527168616 |
10 | 530001143088603 |
11 | 14396924a19924a |
12 | 4b5399325606a3 |
13 | 19996b7c88c214 |
14 | 94c42995601ab |
15 | 414182cc1ee53 |
hex | 1e20881dd45db |
530001143088603 has 8 divisors (see below), whose sum is σ = 706672485027648. Its totient is φ = 353331948270984.
The previous prime is 530001143088601. The next prime is 530001143088649. The reversal of 530001143088603 is 306880341100035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 530001143088603 - 21 = 530001143088601 is a prime.
It is not an unprimeable number, because it can be changed into a prime (530001143088601) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 536204301 + ... + 537191822.
It is an arithmetic number, because the mean of its divisors is an integer number (88334060628456).
Almost surely, 2530001143088603 is an apocalyptic number.
530001143088603 is a deficient number, since it is larger than the sum of its proper divisors (176671341939045).
530001143088603 is a wasteful number, since it uses less digits than its factorization.
530001143088603 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1073560713.
The product of its (nonzero) digits is 207360, while the sum is 42.
Adding to 530001143088603 its reverse (306880341100035), we get a palindrome (836881484188638).
The spelling of 530001143088603 in words is "five hundred thirty trillion, one billion, one hundred forty-three million, eighty-eight thousand, six hundred three".
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